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You should use binomial growth `(a+b)^2 = a^2 + 2ab + b^2` , hence you must substitute 2x for a and 2 because that b together that:

`(2x+2)^2 = (2x)^2 + 2(2x)2 + 2^2`

`(2x+2)^2 = 4x^2 + 8x + 4`

Hence, utilizing binomial expansion yields`(2x+2)^2 = 4x^2 + 8x + 4`...


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You should usage binomial growth `(a+b)^2 = a^2 + 2ab + b^2` , hence you need to substitute 2x for a and 2 because that b together that:

`(2x+2)^2 = (2x)^2 + 2(2x)2 + 2^2`

`(2x+2)^2 = 4x^2 + 8x + 4`

Hence, using binomial growth yields`(2x+2)^2 = 4x^2 + 8x + 4` .

You may additionally write the square the binomial `2x + 2` together the product:

`(2x + 2)(2x + 2)`

Factoring out 2 in every brackets yields:

`2(x+1)*2(x+1) = 4(x+1)(x+1)`

Opening the brackets yields:

`4(x+1)(x+1) = 4(x^2 + x + x + 1)` 

`4(x+1)(x+1) = 4x^2 + 4x + 4x + 4`

Collecting choose terms yields:

4(x+1)(x+1) = 4x^2 + 8x + 4

Hence, widening the binomial 2x + 2 by any kind of methods yields `(2x+2)^2 = 4x^2 + 8x + 4` .

See more: Which Of The Following Creates New Combinations Of Alleles Along One Chromosome?


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