we have actually to uncover where (-1,-4) autumn in those points and yes it´s belongs v the very first set so yes the prize is A
an initial one
Step-by-step explanation:
Due to slope type which is y=mx + b.
You are watching: To which graph does the point (−1, 4) belong?
-1 = x and y = 4.
It walk not show the one due to the fact that it would certainly be equal to X, but it does show the negative
1st Graph is correct.
Step-by-step explanation:
Given: suggest ( -1 , -4 )
To find : Graph in i beg your pardon given point belong.
We find by placing given allude in each graph.
Graph 1).
y ≤ -x + 4
LHS = y = -4
RHS = -x + 4 = -(-1) + 4 = 1 + 4 = 5
LHS ≤ RHS.
So, Given point belong come this graph.
Graph 2).
y ≤ -x - 6
LHS = y = -4
RHS = -x - 6 = -(-1) - 6 = 1 - 6 = -5
LHS ≥ RHS.
So, Given allude does not belong to this graph.
Graph 3).
y ≤ 2x - 3
LHS = y = -4
RHS = 2x - 3 = 2(-1) - 3 = -2 - 3 = -5
LHS ≥ RHS.
So, Given allude does no belong come this graph.
Graph 4).
y ≤ 5x - 1
LHS = y = -4
RHS = 5x - 1 = 5(-1) - 1 = -5 - 1 = -6
LHS ≥ RHS.
So, Given suggest does no belong come this graph.
Therefore, 1st Graph is correct.
Answer from: Spoilmom7231
Option A is correct.
Step-by-step explanation:
Given coordinates of the suggest ( -1 , 4 )
Option A
y ≤ -x + 4
LHS = y = 4
RHS = -x + 4 = -(-1) + 4 = 5
LHS ≤ RHS
So, Given suggest belong to this graph.
Option B
y ≤ -x - 5
LHS = y = 4
RHS = -x - 5 = -(-1) - 5 = -4
LHS ≥ RHS
So, Given suggest does not belong to this graph.
Option C
y ≤ 2x - 3
LHS = y = 4
RHS = 2x - 3 = 2(-1) - 3 = -5
LHS ≥ RHS
So, Given suggest does not belong come this graph.
Option D
y ≤ 5x + 1
LHS = y = 4
RHS = 5x + 1 = 5(-1) + 1 = -4
LHS ≥ RHS
So, Given suggest does not belong to this graph.
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Therefore, option A is correct.
Answer from: ssalazc1593
The answer is y ≤ -x + 4 ⇒ the first answer
Step-by-step explanation:
∵ The allude is (-1 , -4)
∵ y ≤ -x + 4 ⇒ -1 ≤ -(-1) + 4
∴ -1 ≤ 5 ⇒ right inequality
If we try the others
y ≤ -x - 6 ⇒ -1 ≤ -(-1) - 6 ⇒ -1 ≤ -5 no true
y ≤ 2x - 3 ⇒ -1 ≤ 2(-1) - 3 ⇒ -1 ≤ -5 no true
y ≤ 5x - 1 ⇒ -1 ≤ 5(-1) - 1 ⇒ -1 ≤ -6 not true
∴ The prize is an initial one
Answer from: 90317641
By replacing the allude (-1, 4) right into the very first inequality y 4 4 4lksocossiodks8855
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